An unknown metal forms 2 different compounds with oxyge?

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When a 5.5 g sample of the metal combines with oxygen under conditions that form oxide A, 6.99 g of product are formed. When a second 5.5g sample of the metal is combined with oxygen under conditions that form oxide B, 7.74 g of product are formed.

Oxygen’s equivalent weight is 8.

Calculate the equivalent weights of the metal in oxide a and oxide b.
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Any help would be great.. I can’t seem to figure it out!! =0S

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One Response to “An unknown metal forms 2 different compounds with oxyge?”

SciMann on July 28th, 2010 at 12:03 pm

_____Chem analysis (atwt of oxygen is 16g/mole)

_____M___ +___ y/2O2 ——> MxOy
_____5.5g______________gO = (6.99 – 5.5)g
______________________= y moles O = 0.093 mole
_____M___ +___ z/2O2 ——> MwOz
_____5.5g______________gO = (7.74 – 5.5)g
______________________= z moles O = 0.14

ratio z/y = 0.14/0.93 = 1.50

some cmpd pairs: MO, MO3, M2O and M2O3

___MO: atwt M =5.5g /0.093mole = 59 g/mole
___MO3: atwt M = 5.5g / 1/3*0.14mole = 118 g/mole

___M2O: atwt M = 5.5g / (2*0.093 mole) = 29.5 g/mole
___M2O3: atwt M = 5.5g / (2/3*0.14 mole) = 58.9 g/mole

answer:atwt M = 59 g/mole (Co) and oxides are CoO amd Co2O3

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